-6x^2+7x+13=0

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Solution for -6x^2+7x+13=0 equation: 



-6x^2+7x+13=0

a = -6; b = 7; c = +13;
Δ = b2-4ac
Δ = 72-4·(-6)·13
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-19}{2*-6}=\frac{-26}{-12}
=2+1/6
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+19}{2*-6}=\frac{12}{-12}
=-1
$

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